Issue 8, 2003

A series of di-nuclear rhodium(i) complexes with trialkylstibines as bridging ligands

Abstract

Metathetical reactions of [Rh2Cl2(μ-CPh2)2(μ-SbiPr3)] 1 with NaBr and NaI afforded the corresponding di-nuclear complexes [Rh2X2(μ-CPh2)2(μ-SbiPr3)] (X = Br 2, I 3) in practically quantitative yields. Analogous displacement reactions of 1 with equimolar amounts of the sodium salts of acetylacetone (acacH), trifluoracetylacetone (acac-f3-H) and dipivaloylmethane (dpmH) led to the formation of the unsymmetrical rhodium(I) compounds [Rh2(X)Cl(μ-CPh2)2(μ-SbiPr3)] (X = acac 4, acac-f35, dpm 6). From 1 and excess of Na(acac) and Na(dpm), the symmetrical complexes [Rh2X2(μ-CPh2)2(μ-SbiPr3)] (X = acac 7, dpm 8) were formed. Treatment of 7 with acetic acid and trifluoracetic acid in the molar ratio of 1 ∶ 1 gave the unsymmetrical compounds [Rh2X(acac)(μ-CPh2)2(μ-SbiPr3)] (X = CF3CO29, CH3CO210), while with an excess of CR3CO2H the symmetrical complexes [Rh22-O2CR3)2(μ-CPh2)2(μ-SbiPr3)] (R = F 11, H 12) were obtained. The X-ray crystal structure analysis of 12 revealed that analogously to 1 the stibine ligand occupies a symmetrical bridging position. The reactions of 1, 4 and 7 with SbEt3 and Sb(CH2Ph)3 led to bridge-ligand exchange and gave the di-nuclear compounds [Rh2(acac)Cl(μ-CPh2)2(μ-SbEt3)] 13 and [Rh2X(X′)(μ-CPh2)2{μ-Sb(CH2Ph)3}] (X = X′ = Cl 14, X = Cl, X′ = acac 15, X = X′ = acac 16) without cleavage of the [Rh2(μ-CPh2)2] core fragment.

Graphical abstract: A series of di-nuclear rhodium(i) complexes with trialkylstibines as bridging ligands

Supplementary files

Article information

Article type
Paper
Submitted
20 Jan 2003
Accepted
20 Feb 2003
First published
12 Mar 2003

Dalton Trans., 2003, 1495-1499

A series of di-nuclear rhodium(I) complexes with trialkylstibines as bridging ligands

T. Pechmann, C. D. Brandt and H. Werner, Dalton Trans., 2003, 1495 DOI: 10.1039/B300786N

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