Spin Polarized Metastable <span class="aps-inline-formula"><math xmlns="http://www.w3.org/1998/Math/MathML" display="inline"><mi>He</mi><mrow><msup><mrow><mi></mi></mrow><mrow><mi>*</mi></mrow></msup></mrow><mo>(</mo><mrow><msup><mrow><mn>2</mn></mrow><mrow><mn>3</mn></mrow></msup></mrow><mi mathvariant="italic">S</mi><mo>,</mo><mi></mi><mn>1</mn><mi mathvariant="italic">s</mi><mn>2</mn><mi mathvariant="italic">s</mi><mo>)</mo></math></span> Stimulated Desorption of <span class="aps-inline-formula"><math xmlns="http://www.w3.org/1998/Math/MathML" display="inline"><mrow><msup><mrow><mi>H</mi></mrow><mrow><mo>+</mo></mrow></msup></mrow></math></span> Ions

T. Suzuki; M. Kurahashi; Y. Yamauchi; T. Ishikawa; T. Noro

doi:10.1103/PhysRevLett.86.3654

Spin Polarized Metastable $He^{*} (2^{3} S, 1 s 2 s)$ Stimulated Desorption of $H^{+}$ Ions

T. Suzuki, M. Kurahashi, Y. Yamauchi, T. Ishikawa, and T. Noro

Phys. Rev. Lett. 86, 3654 – Published 16 April 2001

Abstract

The yield of $H^{+}$ in the metastable $He^{*} (2^{3} S, 1 s 2 s)$ stimulated desorption (MSD) on an $H_{2} O / Na / Fe$ surface has been found to depend on the spin of the incident $He^{*}$ . By combination with the spin-resolved analysis for the surface electronic structure, it is indicated that the neutralization of the hole in the OH $3 σ$ molecular orbital, which is created by the incident $He^{*}$ , by Na $3 s$ electrons plays a crucial role in the spin polarization of the $H^{+}$ MSD intensity. The dependence of the spin polarization of $H^{+}$ MSD on the kinetic energy of the desorbed $H^{+}$ has been observed, and it is discussed based on the Menzel-Gomer-Readhead model.