Elsevier

Annals of Physics

Volume 323, Issue 12, December 2008, Pages 2971-2986
Annals of Physics

Large momentum part of a strongly correlated Fermi gas

https://doi.org/10.1016/j.aop.2008.03.005Get rights and content

Abstract

It is well known that the momentum distribution of the two-component Fermi gas with large scattering length has a tail proportional to 1/k4 at large k. We show that the magnitude of this tail is equal to the adiabatic derivative of the energy with respect to the reciprocal of the scattering length, multiplied by a simple constant. This result holds at any temperature (as long as the effective interaction radius is negligible) and any large scattering length; it also applies to few-body cases. We then show some more connections between the 1/k4 tail and various physical quantities, including the pressure at thermal equilibrium and the rate of change of energy in a dynamic sweep of the inverse scattering length.

Section snippets

The theorem

Consider an arbitrary number of fermions with mass m in two spin states and , having an s-wave contact interaction with large scattering length a (ar0[1]) between opposite spin states, and confined by any external potential Vext(r). To discuss their momentum distribution, it is convenient to use a box with volume Ω and impose a periodic boundary condition. For a large uniform gas, Ω is its actual volume; but for a gas confined in a trap, it is better to use (conceptually) a very large box

The proof

Although the theorem can be proved with conventional means as well, we shall use the formalism developed in [4]. This formalism, as we shall see below, allows us to prove this universal theorem in a universal (and simple) way.

The basis of the formalism developed in [4] is a pair of linearly independent generalized functions Λ(k) and L(k), satisfyingΛ(k)=1(k<),d3k(2π)3Λ(k)k2=0,L(k)=0(k<),d3k(2π)3L(k)k2=1,Λ(-k)=Λ(k),L(-k)=L(k).There is no contradiction at all, because the integrals of

Two-body case: a conventional proof

It is cumbersome to prove the above theorem with conventional means. Here we just demonstrate the two-body case, and then sketch the extension to the N-body cases. This shall help to convince the readers that the adiabatic sweep theorem is indeed correct, even if they are not used to the succinct (and “unconventional”) proof in the last section.

Now consider two fermions in opposite spin states with an external potential Vext(r). We consider an energy eigenstate described by a wave function ϕ(r1,

Physical meaning

The meaning of Eq. (1) is intuitively clear. If we tune the inverse scattering length slightly and slowly, quantum mechanical first-order perturbation determines the amount by which the energy level shifts. In the limit of zero effective interaction radius, two fermions (in opposite spin states) do not interact unless they appear at the same position, so the energy shift should be proportional to the probability that this occurs. Meanwhile, ΩC characterizes this probability [4]; recall that

Acknowledgments

The author thanks T.L. Ho for a stimulating suggestion, and thanks E. Braaten for comments. He also thanks K. Levin for the introduction to ultracold Fermi gases, and S. Giorgini for communication.

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