Mechanisms of intracellular pH regulation in the hamster inner medullary collecting duct perfused in vitro

Abstract

To examine the mechanisms of H⁺ transport in the mid-inner medullary collecting duct of hamsters, we measured the intracellular pH (pH_i) in the in vitro perfused tubules by microscopic fluorometry using 2′,7′-bis(carboxyethyl)-carboxyfluorescein (BCECF) as a fluorescent probe. In the basal condition, pH_i was 6.74±0.04 (n=45) in HCO ⁻₃ -free modified Ringer solution. Either elimination of Na⁺ from the bath or addition of amiloride (1 mM) to the bath produced a reversible fall in pH_i After acid loading with 25 mM NH₄Cl, pH_i spontaneously recovered with an initial recovery rate of 0.096±0.012 (n=23) pH unit/min. In the absence of ambient Na⁺, after removal of NH ⁺₄ , the pH_i remained low (5.95±0.10, n=8) and showed no signs of recovery. Subsequent restoration of Na⁺ only in the lumen had no effect on pH_i. However, when Na⁺ in the bath was returned to the control level, pH_i recovered completely. Amiloride (1 mM) in the bath completely inhibited the Na⁺-dependent pH_i recovery. Furthermore, elimination of Na⁺ from the bath, but not from the lumen, decreased pH_i from 6.97±0.07 to 6.44±0.05 (n=12) in the HCO ⁻₃ /Ringer solution or 6.70±0.03 to 6.02±0.05 (n=8) in the HCO ⁻₃ free solution. pH_i spontaneously returned to 6.76±0.08 with a recovery rate of 0.017±0.5 pH unit/min in the presence of CO₂/HCO ⁻₃ , whereas it did not recover in the absence of CO₂/HCO ⁻₃ . Although elimination of ambient Na⁺ depolarized the basolateral membrane voltage (V _B) from −78±1.2 to −72 ±0.6 mV (n=5, P<0.01), the level of V _B was not sufficient to explain the pH_i recovery solely by HCO ⁻₃ entry driven by the voltage. These results indicate that (a) pH_i of the inner medullary collecting duct is regulated mainly by a Na⁺/H⁺ exchanger in the basolateral membranes, (b) no apparent Na⁺-dependent H⁺ transport system exists in the luminal membranes and (c) Na⁺-independent H⁺ transport may also operate in the presence of CO₂/HCO ⁻₃